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Backport #3103 traverseFilter
Queue instance to scala_2.11
#3292
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travisbrown
merged 2 commits into
typelevel:scala_2.11
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gagandeepkalra:backport/queueInstances/traverseFilter
Mar 11, 2020
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We can have an implementation without using
Eval
, might even perform a little better (for a bigger queue); without all those extraEval
wrappers.fa.foldRight(G.pure(Queue.empty[B]))( (x, xse) => G.map2(f(x), xse)((i, o) => i.fold(o)(_ +: o)))
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That won't short-circuit, though, right?
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@travisbrown yes agreed it won't, but for the same reason the present implementation wouldn't.
If by short circuit you mean
f
wouldn't have to run on the remaining Queue elements (given we are folding from the right).This is my understanding and derived reasoning-
map2Eval
short-circuits: given the underlyingG
structure allows it, then theEval
argument skips running.In this case however, the Eval description is computed by running
f
on each element of theQueue
already. The first argument tomap2Eval
is notLazy
. In every situationf
will run on each element.Please correct me If I understood this wrongly.
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I see it now, we are using the wrong
foldRight
here, queue.foldRight ends up with a while loop (standard library). This should have been-traverse.foldRight[A, G[Queue[B]]](fa, Always(G.pure(Queue.empty))) { (a, lglb) => G.map2Eval(f(a), lglb)((i, o) => i.fold(o)(_ +: o)) } .value
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I see the same problem with other
traverseFilter
implementations, should I open a new issue?