how to take ownership from state?

[Xiaobaishushu25]

i use state to manage a oneshot sender:

     let (send,recv) = oneshot::channel::<()>();
     app.manage(send);

but when i want to use the sender to send a message, thie is some error:

#[tauri::command]
pub fn exit_app(send:State<'_, Sender<()>) {
    send.send(()).expect("send error");
    exit(0)
}

the send.send(()) has error that 'cant move' because the function send() will consume it self.
i also cant use clone() because Sender not implemented.
i also try Mutex ,it has the same problem:

#[tauri::command]
pub fn exit_app(send:State<'_, Mutex<Sender<()>>>) {
    (send.lock().unwrap()).send(()).expect("send error");
    exit(0)
}

i also try take():

#[tauri::command]
pub fn exit_app<'r>(mut send:State<'r, Option<Sender<()>>>) {
    let option = send.take();
    option.unwrap().send(()).expect("send error");
    exit(0)
}

but it also error:error[E0596]: cannot borrow data in dereference of tauri::State<'_, std::option::Option<tokio::sync::oneshot::Sender<()>>> as mutable.
do you have any suggestion to sovle the problem? thanks.

[FabianLars]

You were really close actually! If you combine your last 2 tries into Mutex<Option<Sender>> it should work

[Xiaobaishushu25]

You were really close actually! If you combine your last 2 tries into Mutex<Option<Sender>> it should work

Thank you for your prompt reply. I have made it work like this:

#[tauri::command]
pub async fn exit_app(send:State<'_, Mutex<Option<tokio::sync::oneshot::Sender<()>>>>)->Result<(),()> {
    send.lock().unwrap().take().unwrap().send(()).unwrap();
    exit(0)
}