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allow generic compileTime proc folding #22022
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935553f
allow generic compileTime procs?
metagn 6fa0c1c
rebase, add faithful test for #19365
metagn 399c7fd
better original patch + don't constant fold calls in `typeof`
metagn 1f0fea5
consider nested expression in typeof
metagn 2227562
revert isGenericRoutineStrict?
metagn 7f3258b
getting more derailed
metagn bb3bbfd
might as well try isGenericRoutineStrict again
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Original file line number | Diff line number | Diff line change |
---|---|---|
@@ -0,0 +1,29 @@ | ||
block: # issue #10753 | ||
proc foo(x: int): int {.compileTime.} = x | ||
const a = foo(123) | ||
doAssert foo(123) == a | ||
|
||
proc bar[T](x: T): T {.compileTime.} = x | ||
const b = bar(123) | ||
doAssert bar(123) == b | ||
const c = bar("abc") | ||
doAssert bar("abc") == c | ||
|
||
block: # issue #22021 | ||
proc foo(x: static int): int {.compileTime.} = x + 1 | ||
doAssert foo(123) == 124 | ||
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||
block: # issue #19365 | ||
proc f[T](x: static T): T {.compileTime.} = x + x | ||
doAssert f(123) == 246 | ||
doAssert f(1.0) == 2.0 | ||
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||
block: | ||
# don't fold compile time procs in typeof | ||
proc fail[T](x: T): T {.compileTime.} = | ||
doAssert false | ||
x | ||
doAssert typeof(fail(123)) is typeof(123) | ||
proc p(x: int): int = x | ||
|
||
type Foo = typeof(p(fail(123))) |
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As you can see here we already have
efInTypeof
. Can this be used instead ofc.inTypeofContext
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That's what I tried first, it doesn't always propagate, even in simple cases like
typeof(foo(compileTimeProc()))
where it's nested in another call.