Invalid deserialization

[wlad031]

Hello

I have the following code:

class A {
public:
    float f;

    A() {}

    A(float f) :
            f(f) {}
};

namespace json_dto {
    template<typename JSON_IO>
    void json_io(JSON_IO& io, A a) {
        io
        & json::mandatory("f", a.f);
    }
}

After

auto v1 = A(10.8);
auto v = json_dto::to_json(v1);
std::cout << v << std::endl;
auto v2 = json_dto::from_json<A>(v);
std::cout << json_dto::to_json(v2) << std::endl;

I get
{"f":10.800000190734864}
{"f":1041031353073664.0}

Could you please help, where is my mistake?

[ngrodzitski]

Try this signature for jsob_io function: json_io(JSON_IO& io, A & a) Pass A instance by ref. 9 сент. 2017 г. 11:49 AM пользователь "Vladislav Gerasimov" < [email protected]> написал: Hello I have the following code: class A { public: float f; A() {} A(float f) : f(f) {} }; namespace json_dto { template<typename JSON_IO> void json_io(JSON_IO& io, A a) { io & json::mandatory("f", a.f); } } After auto v1 = A(10.8); auto v = json_dto::to_json(v1); std::cout << v << std::endl; auto v2 = json_dto::from_json<A>(v); std::cout << json_dto::to_json(v2) << std::endl; I get {"f":10.800000190734864} {"f":1041031353073664.0} Could you please help, where is my mistake? — You are receiving this because you are subscribed to this thread. Reply to this email directly, view it on GitHub <#5>, or mute the thread <https://github.com/notifications/unsubscribe-auth/AVt3Yj6c30BCEl90sT2Ro3ptH93xisSvks5sglEsgaJpZM4PR7o-> .

[wlad031]

Thank you, it was my fault.

One more question: is there a way to set precision for float and double values (for getting {"f":10.8})?

[ngrodzitski]

in a current version there is no way to set precision. A cuple of times I've faced such issue I simply do such rounding myself.
But seems like it is a not a rare cese, so I'll think of a some kind of format option.