Simplify the way to compute the remainder modulo 3 in PDF20Hash function #15548
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I noticed the 256 % 3 (which is equal to 1) so I slighty simplify the code. The sum of the 16 Uint8 doesn't exceed 2^12, hence we can just take the sum modulo 3.
Snuffleupagus
approved these changes
Oct 7, 2022
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/botio test |
From: Bot.io (Linux m4)ReceivedCommand cmd_test from @calixteman received. Current queue size: 0 Live output at: http://54.241.84.105:8877/4be2924866eca42/output.txt |
From: Bot.io (Windows)ReceivedCommand cmd_test from @calixteman received. Current queue size: 0 Live output at: http://54.193.163.58:8877/df49069c069074f/output.txt |
From: Bot.io (Linux m4)FailedFull output at http://54.241.84.105:8877/4be2924866eca42/output.txt Total script time: 25.53 mins
Image differences available at: http://54.241.84.105:8877/4be2924866eca42/reftest-analyzer.html#web=eq.log |
From: Bot.io (Windows)FailedFull output at http://54.193.163.58:8877/df49069c069074f/output.txt Total script time: 30.50 mins
Image differences available at: http://54.193.163.58:8877/df49069c069074f/reftest-analyzer.html#web=eq.log |
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I noticed the 256 % 3 (which is equal to 1) so I slightly simplify the code. The sum of the 16 Uint8 doesn't exceed 2^12, hence we can just take the sum modulo 3.