CodingQuizzes

My repository for coding quizzes that I post on social media like linkedin. A code snippet a day keeps the bordome away. :)

Idea:

Every once in while, whenever I find something interesting/inspiring that cound be used to challenge basic coding skills, I will collect these ideas and publish a little coding quiz.

Concept:

Abstract quiz questions from actual coding situation & Try to solve this question in python & C. BUT, try is by your own. Do not use ChatGTP:)

Quizzes:

|2022/12/17|

Q: Swap two numbers (e.g. a=3 and b=5) without a third variable.

|2022/12/20|

Q: How to find out if given two strings (e.g. "Happy Birthday Brian" & "B RaIN day th Happy Bir ") are anagrams or not?

|2023/04/13|

Q: How to access a value in a nested dict of different depths with a list containing lists of keys. If a key does not exist, a default value should be returned. If the key being accessed contains another dict, that dict should be returned.

Use the following nested dict:

nested_dict = {"1": {"11": "Hello,",
                     "12": 42,
                     "13": {"131": "this",
                            "132": {"1321": "is",
                                    "1322": 42,
                                    "1323": "a"
                                   }
                            }
                     },
               "2":   42,
               "3": {"31": "nested",
                     "32": 42,
                     "33": "dict",
                    },
               "4": "!"
             }

Use the following key list to access the values in the nested dict:

    keys_list = [['1','11'],
                 ['1','13','131'],
                 ['1','13','132','1321'],
                 ['1','13','132','1323'],
                 ['3','31'],
                 ['3','33'],
                 ['4']
                ]          
Output: Hello, this is a nested dict !

Furthermore, the following key lists can be used to test your code:
test case 1: first level key + key that is not present + key that is present

    keys_list = [['3'],
                 ['1','11','111'],
                 ['2']
                ]
Output: {'31': 'nested', '32': 42, '33': 'dict'} key not present 42

test case 2: whole nested dict

    keys_list = [[]
                ]
Output: {'1': {'11': 'Hello,', '12': 42, '13': {'131': 'this', '132': {'1321': 'is', '1322': 42, '1323': 'a'}}}, '2': 42, '3': {'31': 'nested', '32': 42, '33': 'dict'}, '4': '!'}