cron-utils fails to describe weekday list

[PrasadaRaoK]

When we select cron expression as weekly Monday and Tuesday the expression is coming like
0 0 0 ? * MON,TUE *

exception got while parsing the cron expression.

in hours tab

[jmrozanec]

@PrasadaRaoK Thank you for using cron-utils! May I ask you for a test to reproduce the issue? I am unable to reproduce it for now. Below I paste the test I created:

CronParser parser = new CronParser(CronDefinitionBuilder.instanceDefinitionFor(CronType.QUARTZ));
parser.parse("0 0 0 ? * MON,TUE *");
//works as expected

[jmrozanec]

@PrasadaRaoK Please provide a test to reproduce the issue. Otherwise we will close the issue as unable to reproduce. Thank you!

[PrasadaRaoK]

I used the below code to parse the expression "0 0 0 ? * MON,TUE *"

I tried with your code also
CronParser parser = new CronParser(CronDefinitionBuilder.instanceDefinitionFor(CronType.QUARTZ));

---

CronDefinition cronDefinition = CronDefinitionBuilder.defineCron()
.withSeconds().and()
.withMinutes().and()
.withHours().and()
.withDayOfMonth()
.supportsHash().supportsL().supportsLW().supportsW().supportsQuestionMark().and()
.withMonth().and()
.withDayOfWeek()
.withMondayDoWValue(1)
.withIntMapping(7, 0)
.supportsHash().supportsL().supportsLW().supportsW().supportsQuestionMark().and()
.withYear().and()
.lastFieldOptional()
.instance();

        CronParser parser = new CronParser(cronDefinition);
        Cron quartzCron = parser.parse(cronExpression);
        CronDescriptor descriptor = CronDescriptor.instance(Locale.ENGLISH);
        readableExpression = descriptor.describe(quartzCron);

[jmrozanec]

@PrasadaRaoK Thank you for providing the example. I was able to reproduce it and created a test for it. The issue happens when describing the cron pattern. I found where it lays; still need to find a good way to fix this.

[jmrozanec]

@PrasadaRaoK Issue fixed!