Update 0180.(Medium) Consecutive Numbers.sql

haibarawu · Jun 4, 2020 · d0baf24 · d0baf24
1 parent 4f8e526
commit d0baf24
Showing 1 changed file with 23 additions and 5 deletions.
diff --git a/Database/0180.(Medium) Consecutive Numbers.sql b/Database/0180.(Medium) Consecutive Numbers.sql
@@ -1,9 +1,23 @@
 /****************************************************************************************************
-0180. Consecutive Numbers
+180. Consecutive Numbers
+180. 连续出现的数字
 
 Difficulty: Medium
 
 Write a SQL query to find all numbers that appear at least three times consecutively.
+编写一个 SQL 查询，查找所有至少连续出现三次的数字。
+
+SQL 架构：
+Create table If Not Exists Logs (Id int, Num int)
+Truncate table Logs
+insert into Logs (Id, Num) values ('1', '1')
+insert into Logs (Id, Num) values ('2', '1')
+insert into Logs (Id, Num) values ('3', '1')
+insert into Logs (Id, Num) values ('4', '2')
+insert into Logs (Id, Num) values ('5', '1')
+insert into Logs (Id, Num) values ('6', '2')
+insert into Logs (Id, Num) values ('7', '2')
+
 +----+-----+
 | Id | Num |
 +----+-----+
@@ -37,9 +51,13 @@ FROM (
 WHERE Num = lag AND Num = lead
 
 
+/****************************************************************************************************/
+
+
 --Method2:
-SELECT DISTINCT l1.Num AS ConsecutiveNums 
-FROM Logs l1, Logs l2, Logs l3
-WHERE l1.Id = l2.Id - 1 AND l2.Id = l3.Id - 1 
-    AND l1.Num = l2.Num AND l2.Num = l3.Num
+SELECT DISTINCT l1.Num AS ConsecutiveNums
+FROM Logs AS l1, Logs AS l2, Logs AS l3
+WHERE l1.Id = l2.Id - 1 AND l2.Id = l3.Id - 1
+AND l1.Num = l2.Num AND l2.Num = l3.Num
+