Update 0627.(Easy) Swap Salary.sql

Database/0627.(Easy) Swap Salary.sql

@@ -1,14 +1,26 @@
 /****************************************************************************************************
 627. Swap Salary
+627. 交换工资
 
 Difficulty: Easy
 
 https://leetcode.com/problems/swap-salary/
 https://leetcode.com/articles/swap-salary/
 
+SQL Schema:
+create table if not exists salary(id int, name varchar(100), sex char(1), salary int)
+Truncate table salary
+insert into salary (id, name, sex, salary) values ('1', 'A', 'm', '2500')
+insert into salary (id, name, sex, salary) values ('2', 'B', 'f', '1500')
+insert into salary (id, name, sex, salary) values ('3', 'C', 'm', '5500')
+insert into salary (id, name, sex, salary) values ('4', 'D', 'f', '500')
+
 Given a table salary, such as the one below, that has m=male and f=female values. 
 Swap all f and m values (i.e., change all f values to m and vice versa) with a single update statement and no intermediate temp table.
 Note that you must write a single update statement, DO NOT write any select statement for this problem.
+给定一个 salary 表，如下所示，有 m = 男性 和 f = 女性 的值。
+交换所有的 f 和 m 值（例如，将所有 f 值更改为 m，反之亦然）。要求只使用一个更新（Update）语句，并且没有中间的临时表。
+注意，您必只能写一个 Update 语句，请不要编写任何 Select 语句。
 
 Example:
 | id | name | sex | salary |
@@ -34,6 +46,9 @@ UPDATE salary
 SET sex = IIF(sex = 'm', 'f', 'm')
 
 
+/****************************************************************************************************/
+
+
 --Method2:
 UPDATE salary
 SET sex =