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Attenuation tomography #311

Answered by halbmy
sminize asked this question in Q&A
Apr 30, 2021 · 12 comments · 16 replies
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Just to get things right, the attenuation coefficient a defines the relative loss of amplitude A per ray path length

a = - 1/A dA/dl

So the amplitude after passing a cell is A=A0 exp(- a l) (A0 being the initial amplitude).

The logarithmized relative amplitude is

log(A/A0) = - integral a dl

and can be expressed as matrix-vector product of the attenuation coefficient vector by the Jacobian (way path) matrix -W a.

But how do you know the initial amplitude A0? And do you have to take into account spherical attenuation (i.e. energy distributes on spheres of increasing size)?

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