Merge pull request #1441 from SohilP25/master

DSA & CP Interview Question For Preparation

Program's_Contributed_By_Contributors/C++/5_Sort_Colors.cpp

@@ -0,0 +1,66 @@
+// Problem Question :  https://leetcode.com/problems/sort-colors/
+// WARN : DUTCH NATIONAL FLAG ALGORITHM IS HERE (><)
+#include <bits/stdc++.h>
+using namespace std;
+#define ll long long
+#define endl '\n'
+
+//Solution 1(DUTCH NATONAL FLAG ALGO.)
+class Solution {
+public:
+    void sortColors(vector<int>& nums) {
+      int low = 0;
+        int mid = 0;
+        int hi = nums.size() - 1;
+
+        while(mid<=hi)
+        {
+            switch(nums[mid])
+            {
+                    // If Element is 0
+                case 0 :
+                    swap(nums[mid++],nums[low++]);
+                    break;
+                    // If Element is 1
+                case 1 : 
+                    mid++;
+                    break;
+                    // If Element is 2
+                case 2 :
+                    swap(nums[mid],nums[hi--]);
+                    break;
+            }
+        }
+    }
+};
+
+
+// Solution 2(MY SOLN.)
+class Solution2 {
+public:
+    void sortColors(vector<int>& nums) {
+        int c0=0,c1=0;
+        for(auto i : nums)
+        {
+            if(i==0)
+                c0++;
+            else if(i==1)
+                c1++;
+        }
+        for(int i = 0 ; i < c0 ; i++){
+            nums[i] = 0;
+        }
+        for(int i = c0 ; i < (c0+c1) ; i++){
+            nums[i] = 1;
+        }
+        for(int i = (c0+c1); i < nums.size() ; i++ ){
+            nums[i] = 2;
+        }
+    }
+};
+
+int main(){
+ios::sync_with_stdio(0); 
+cin.tie(0);
+    return 0;
+}

Program's_Contributed_By_Contributors/C++/6_stock_buy_and_sell.cpp

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+// Problem Question : https://leetcode.com/problems/best-time-to-buy-and-sell-stock/
+#include <bits/stdc++.h>
+using namespace std;
+#define ll long long
+#define endl '\n'
+// Solution 1 : Optimal
+class Solution {
+public:
+    int maxProfit(vector<int>& prices) {
+        int mini = INT_MAX;
+        int profit = 0;
+        for(int i = 0 ; i < prices.size() ; i++)
+        {
+            mini = min(mini,prices[i]);
+            profit = max(profit,prices[i] - mini);
+        }
+        return profit;
+    }
+};
+
+// Solution 2 :  Bruteforce
+class Solution {
+public:
+    int maxProfit(vector<int>& prices) {
+        int profit = 0;
+        for(int i = 0 ; i < prices.size() ; i++)
+        {
+            for(int j = i+1 ; j<prices.size() ; j++)
+            {
+                if(prices[j] > prices[i]){
+                    profit = max(prices[j] - prices[i],profit);
+                 }
+            }
+        }
+                    return profit;
+
+    }
+};
+int main(){
+ios::sync_with_stdio(0); 
+cin.tie(0);
+
+    return 0;
+}

Program's_Contributed_By_Contributors/C++/7_rotate_image.cpp

@@ -0,0 +1,28 @@
+//Problem Question : https://leetcode.com/problems/rotate-image/
+#include <bits/stdc++.h>
+using namespace std;
+#define ll long long
+#define endl '\n'
+// Solution : 
+class Solution {
+public:
+    void rotate(vector<vector<int>>& matrix) {
+        int n = matrix.size();
+        //First Transpose matrix means {i,j} <-> {j,i}
+        for(int i = 0; i < n ; i++){
+            for(int j = 0 ; j < i ; j++){
+                swap(matrix[i][j],matrix[j][i]);
+            }
+        }
+        //Reverse every row 
+        for(int i = 0 ; i < n ; i++){
+            reverse(matrix[i].begin(),matrix[i].end());
+        }
+    }
+};
+int main(){
+ios::sync_with_stdio(0); 
+cin.tie(0);
+
+    return 0;
+}

Program's_Contributed_By_Contributors/C++/8_Merge_intervals.cpp

@@ -0,0 +1,38 @@
+//Problem Question : https://leetcode.com/problems/merge-intervals/
+#include <bits/stdc++.h>
+using namespace std;
+#define ll long long
+#define endl '\n'
+
+//solution :
+
+class Solution {
+public:
+    vector<vector<int>> merge(vector<vector<int>>& intervals) {
+        vector<vector<int>> v;
+         if( intervals.size() ==0){
+            return v;
+        }
+        sort(intervals.begin(),intervals.end());
+        vector<int> temp = intervals[0];  
+       for(auto it : intervals){
+           if(temp[1] >= it[0]){
+               temp[1] = max(temp[1], it[1]);
+           }
+           else{
+               v.push_back(temp);
+               temp = it;
+           }
+       }
+        v.push_back(temp);
+        return v;
+    }
+};
+
+int main()
+{
+    ios::sync_with_stdio(0);
+    cin.tie(0);
+
+    return 0;
+}

Program's_Contributed_By_Contributors/C++/9_Merge_sorted_array.cpp

@@ -0,0 +1,91 @@
+//Problem Question : https://leetcode.com/problems/merge-sorted-array/
+#include <bits/stdc++.h>
+using namespace std;
+#define ll long long
+#define endl '\n'
+// Time complexity: O(logn)
+// Space Complexity: O(1)
+//Solution 1 :
+class Solution {
+public:
+    void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) {
+        for(int k = m ; k <( m+n) ; k++ )
+        {
+            nums1[k] = nums2[k-m];
+        }
+        if((m == 0) || (n == 0) )
+        {
+            return;
+        }
+        int gap = ceil(((m+n)/2.0));
+        while(gap > 0 ){
+            int i = 0 ;
+            int j =gap;
+            while(j < (m+n))
+            {
+                if(nums1[i] > nums1[j])
+                {
+                    swap(nums1[i],nums1[j]);
+                }
+                i++;
+                j++;
+            }
+            if(gap == 1 ){
+                break;}
+                gap = ceil(gap/2.0);
+        }
+    }
+};
+
+// Time complexity: O(n*m) + O(n)
+// Space Complexity: O(1) 
+//Solution 2 :
+class Solution {
+public:
+    void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) {
+        for(int i = m ; i <( m+n) ; i++ )
+        {
+            nums1[i] = nums2[i-m];
+        }
+        if((nums1.size() == 0) || (nums2.size() == 0) )
+        {
+            return;
+        }
+        int i = 0;
+        while(i != m )
+        {
+            if(nums1[i] > nums1[m]){
+                swap(nums1[i],nums1[m]);
+                sort(nums1.begin() + m ,nums1.end());
+            }
+            i++;
+        }
+    }
+};
+
+//BRUTEFORCE APPROCH : IF YOU DON'T WANT TO MAKE COMPLEX ;)
+//Solution 3 :
+// Time complexity: O(n*log(n))+O(n)
+// Space Complexity: O(1) 
+class Solution {
+public:
+    void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) {
+        for(int i = m ; i <( m+n) ; i++ )
+        {
+            nums1[i] = nums2[i-m];
+        }
+        if((nums1.size() == 0) || (nums2.size() == 0) )
+        {
+            return;
+        }
+        sort(nums1.begin(),nums1.end());
+    }
+};
+
+int main()
+{
+    ios::sync_with_stdio(0);
+    cin.tie(0);
+
+    return 0;
+}