Renamed: lambda.py -> package.py

It seems that lambda.py is a confusable name and we have the package.tf file so it's better to name the helper as package.py to make it associated as a companion script for the package.tf file.
terraform-aws-modules · Jun 9, 2020 · 0f7d1ff · 0f7d1ff
1 parent 1381fd8
commit 0f7d1ff
Show file tree

Hide file tree

Showing 2 changed files with 3 additions and 3 deletions.
diff --git a/lambda.py → package.py b/lambda.py → package.py
diff --git a/package.tf b/package.tf
@@ -3,7 +3,7 @@
 data "external" "archive_prepare" {
   count = var.create && var.create_package ? 1 : 0
 
-  program     = ["python3", "${path.module}/lambda.py", "prepare"]
+  program     = ["python3", "${path.module}/package.py", "prepare"]
   working_dir = path.cwd
 
   query = {
@@ -24,7 +24,7 @@ data "external" "archive_prepare" {
     runtime          = var.runtime
     source_path      = var.source_path
     hash_extra       = var.hash_extra
-    hash_extra_paths = jsonencode(["${path.module}/lambda.py"])
+    hash_extra_paths = jsonencode(["${path.module}/package.py"])
   }
 }
 
@@ -50,7 +50,7 @@ resource "null_resource" "archive" {
   }
 
   provisioner "local-exec" {
-    interpreter = ["python3", "${path.module}/lambda.py", "build",
+    interpreter = ["python3", "${path.module}/package.py", "build",
                   "--timestamp", data.external.archive_prepare[0].result.timestamp]
     command     = data.external.archive_prepare[0].result.build_plan_filename
     working_dir = path.cwd