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Copy path053_Maximum_Subarray.py
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053_Maximum_Subarray.py
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# Author: cym
class Solution:
def maxSubArray(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
# ******* Kadene Algorithm ***********
# max_sum = nums[0]
# if len(nums) > 1:
# tmp_sum = 0
# for i in range(len(nums)):
# tmp_sum += nums[i]
# if tmp_sum > max_sum:
# max_sum = tmp_sum
# if tmp_sum < 0:
# tmp_sum = 0
# return max_sum
# ******* Divide & Conquer Approach ***********
length = len(nums)
if length == 1:
return nums[0]
mid = length//2
left = self.maxSubArray(nums[:mid])
right = self.maxSubArray(nums[mid:])
s1 = nums[mid-1]
left_sum = 0
for i in nums[:mid][::-1]:
left_sum += i
if left_sum > s1:
s1 = left_sum
s2 = nums[mid]
right_sum = 0
for j in nums[mid:]:
right_sum += j
if right_sum > s2:
s2 = right_sum
sum_val = s1+s2
if sum_val < left:
sum_val = left
if sum_val < right:
sum_val = right
return sum_val