Use awk when untrashing files

Need to get the filename from a file that looks like:

	[Trash Info]
	Path=/home/ben/myprojects/vv/f(o)o%5C'&$%7Bx%7D%3C%7C%3E!.gif
	DeletionDate=Y-05-20T15:44:21

Previously was doing `eval $(grep Path filename.info)` to set Path,
but that was silly as certain metacharacters that are special to the
shell are not special to URIs and aren't percent encoded. [Okay, to be
honest, using "eval" is always silly.]

Fixed it by simply using awk instead of grep so I could output just
the filename. That replaces a dozen lines of kludges to make it work
(+ more lines of comments for explanations) with a single line. Yay!

Author: hackerb9

vv

@@ -2193,24 +2193,6 @@ unuriescape() {
     echo
 }
 
-uriescapeshell() {
-    # Given a string that has already been URI escaped, also
-    # percent-escape the characters that would confuse eval. 
-    # Any data after a newline are ignored. 
-
-    # These characters will already be URI encoded: "#%< >[\]^`{|}
-    # So all we need to encode are: $&'()
-
-    sed -n '1 {
-		       s#\$#%24#g;
-		       s#&#%26#g;
-		       s#'\''#%27#g;
-		       s#(#%28#g;
-		       s#)#%29#g;
-		       p
-	      }'
-}
-
 untrash() {
     # untrash: Take the most recent file out of ~/.local/share/Trash/files.
     #
@@ -2246,15 +2228,7 @@ untrash() {
 	fi
     done
 
-
-    local infoline=$(grep 'Path=' "$infofile" | uriescapeshell)
-    if [[ -z "$infoline" ]]; then
-	E "$infofile does not contain a valid Path" >&2
-	return 1
-    fi	
-
-    local Path
-    eval "$infoline"
+    local Path=$(awk -e '/^Path=/ {print substr($0,6); exit;}' "$infofile")
     Path=$(unuriescape "$Path")
 
     # Does directory even existing for us to write to?