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cmd/compile: deal with constructed types that have shapes in them
We convert type args to shape types inside instantiations. If an instantiation constructs a compound type based on that shape type and uses that as a type arg to another generic function being called, then we have a type arg with a shape type embedded inside of it. In that case, we need to substitute out those embedded shape types with their underlying type. If we don't do this, we may create extra unneeded shape types that have these other shape types embedded in them. This may lead to generating extra shape instantiations, and a mismatch between the instantiations that we used in generating dictionaries and the instantations that are actually called. Updates #51303 Change-Id: Ieef894a5fac176cfd1415f95926086277ad09759 Reviewed-on: https://go-review.googlesource.com/c/go/+/387674 Reviewed-by: Keith Randall <[email protected]> Trust: Dan Scales <[email protected]> Run-TryBot: Dan Scales <[email protected]> TryBot-Result: Gopher Robot <[email protected]>
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// run -gcflags=-G=3 | ||
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// Copyright 2022 The Go Authors. All rights reserved. | ||
// Use of this source code is governed by a BSD-style | ||
// license that can be found in the LICENSE file. | ||
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package main | ||
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import ( | ||
"fmt" | ||
) | ||
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func main() { | ||
x := [][]int{{1}} | ||
y := [][]int{{2, 3}} | ||
IntersectSS(x, y) | ||
} | ||
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type list[E any] interface { | ||
~[]E | ||
Equal(x, y E) bool | ||
} | ||
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// ss is a set of sets | ||
type ss[E comparable, T []E] []T | ||
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func (ss[E, T]) Equal(a, b T) bool { | ||
return SetEq(a, b) | ||
} | ||
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func IntersectSS[E comparable](x, y [][]E) [][]E { | ||
return IntersectT[[]E, ss[E, []E]](ss[E, []E](x), ss[E, []E](y)) | ||
} | ||
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func IntersectT[E any, L list[E]](x, y L) L { | ||
var z L | ||
outer: | ||
for _, xe := range x { | ||
fmt.Println("xe", xe) | ||
for _, ye := range y { | ||
fmt.Println("ye", ye) | ||
fmt.Println("x", x) | ||
if x.Equal(xe, ye) { | ||
fmt.Println("appending") | ||
z = append(z, xe) | ||
continue outer | ||
} | ||
} | ||
} | ||
return z | ||
} | ||
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func SetEq[S []E, E comparable](x, y S) bool { | ||
fmt.Println("SetEq", x, y) | ||
outer: | ||
for _, xe := range x { | ||
for _, ye := range y { | ||
if xe == ye { | ||
continue outer | ||
} | ||
} | ||
return false // xs wasn't found in y | ||
} | ||
return true | ||
} |
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xe [1] | ||
ye [2 3] | ||
x [[1]] | ||
SetEq [1] [2 3] |