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LongestSubstringWithoutRepeat.java
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package jpa.example.demo.algo;
/**
* Given a string, find the length of the longest substring without repeating characters.
*
* Example 1:
* * Input: "abcabcbb"
* Output: 3
* Explanation: The answer is "abc", with the length of 3.
*
* Example 2:
* * Input: "bbbbb"
* Output: 1
* Explanation: The answer is "b", with the length of 1.
*
* Example 3:
* * Input: "pwwkew"
* Output: 3
* Explanation: The answer is "wke", with the length of 3.
* Note that the answer must be a substring, "pwke" is a subsequence and not a substring.
*/
public class LongestSubstringWithoutRepeat {
public static void main(String[] args) {
Solution solution = new Solution();
String s1 = "abcabcbb";
String s2 = "bbbbb";
String s3 = "pwwkew";
String s4 = "aab";
String s5 = "dvdf";
System.out.println("sol: " + 3);
System.out.println(solution.lengthOfLongestSubstring(s1));
System.out.println("sol: " + 1);
System.out.println(solution.lengthOfLongestSubstring(s2));
System.out.println("sol: " + 3);
System.out.println(solution.lengthOfLongestSubstring(s3));
System.out.println("sol: " + 2);
System.out.println(solution.lengthOfLongestSubstring(s4));
System.out.println("sol: " + 3);
System.out.println(solution.lengthOfLongestSubstring(s5));
}
}
class Solution {
public int lengthOfLongestSubstring(String s) {
int index = 0;
String max = "";
String preMax = "";
while (index < s.length()) {
for (int i = index; i < s.length(); i++) {
char c = s.charAt(i);
if (!max.contains(String.valueOf(c))) {
max += c;
continue;
}
break;
}
if (max.length() > preMax.length()) {
preMax = max;
}
max = "";
index++;
}
return Math.max(max.length(), preMax.length());
}
// public int lengthOfLongestSubstring(String s) {
// String preMax = "";
// String max = "";
//
// for (int i = 0; i < s.length(); i++) {
// char c = s.charAt(i);
// if (!max.contains(String.valueOf(c))) {
// max += c;
// continue;
// }
// if (preMax.length() < max.length()) {
// preMax = max;
// }
// max = "" + c;
// }
// System.out.println(preMax + " / " + max);
// return Math.max(max.length(), preMax.length());
// }
}