Is it possible to access the compiled qiskit circuit?

[MatthiasReumann]

Hey folks!

Is it somehow possible to access the underlying qiskit circuit after defining the problem?
At first glance, I haven't found anything in the documentation or forum.

For example:

qaoa = QAOA()

simulator = create_device(location='local', name='qiskit.statevector_simulator')
qaoa.set_device(simulator)
qaoa.set_backend_properties(n_shots=1024, seed_simulator=1)
qaoa.compile(knapsack_ising_encoding)

circuit = qaoa.get_circuit() # ???

Thanks.

[MatthiasReumann]

It turns out: Yes, using qaoa.backend.parametric_circuit.