Cannot implement protected interface member as protected?

[JesseRussell411]

I'm a little confused here. An interface can have a protected member, like this:

interface IFoo{
    protected int getInternalInt(); // <------------------ protected member

    public int useInternalInt(){
        return getInternalInt() + 1;
    }
}

But a class that implements the interface cannot make that member's implementation protected like this:

class Foo : IFoo {
    protected int getInternalInt() => 42;
}

It seems that the implementation has to be public. Then there's no error.

But why does it have to be public when the interface member is protected? The interface doesn't require the member to be public.

In fact, if you add a default implementation to the interface, then you can make the class's implementation protected. No error.

[KennethHoff]

In your default interface case; is that actually an implementation of the interface, or just a coincidental name overlap?

[zms9110750]

interface IFoo
{
	protected int getInternalInt();

	public static void Hello(IFoo foo)
	{
		foo.getInternalInt();//How do we call it here? 
	}
}
class Foo : IFoo
{
	public int getInternalInt()//If this method is protected
	{
		throw new NotImplementedException();
	}
}