Python 3.6 or above is required.
Type python -m emlpd lang=en_en in the terminal.
You need to follow the hints given to you in the game interface to defeat the
Evil. To defeat the Evil, you need to make the Evil's HP 0 or less and your HP
above 0.
At the beginning of each round, the game will tell you the counts of true and
false bullets are in the main clip. Each turn, you can choose to shoot at
yourself or the opposite.
If you shoot at yourself and all the bullets are false bullets and do not
explode, you will shoot again in the next turn, otherwise the opposite will
shoot.
If 1 true bullet is shot, it causes 1 point of base damage (may be defended
against).
Each shot has a chance of exploding (i.e., making the bullet act to the
opposite; can be changed with a tool), see Tool 21: Pò Qiāng.
If a side has a hurting point of n(0≤_n_≤8,n_∈N), then for each point of
true bullet damage to the opposite, there is a probability of n/8 that it
will result in an additional HP of damage, and a probability of 1−_n/8 that it
will result in a hurting point plus 1. Hurting point is initially 0.
If a side has m(0≤_m_≤32,_m_∈N) and a hurting point of
n(0≤_n_≤8,n_∈N), and if m>0, then this side's stamina decrease by 1
for each shot. Each turn this side's stamina has a 1/(n+1) probability of
increasing by 1. When m<8, there is a probability of 1−_m/8 of that this
side will get dazed for a turn.
If a side have n(_n_∈N₊) dazing turns, then if it would have been this
side to shoot in the next turn, then the opposite still shoots in the next turn
and the number of this side's dazing turns becomes _n_−1.
Shooting 1 time is called 1 turn.
Giving 1 new clips is called 1 round.
Changing 1 new Evil is called 1 period.
Game running 1 time is called 1 game.
Decrease your stacked badguns by 1 if Pò Qiāng is used by the opposite,
otherwise increase your stacked goodgun(foo) by 1.
See Tool 21: Pò Qiāng
Decrease your stacked badguns by 1 if Pò Qiāng is used by the opposite,
otherwise increase your stacked goodgun(bar) by 1.
See Tool 21: Pò Qiāng
If n(_n_∈N) Xiǎo Dāos is used this turn, attach n points of additional damage for each true bullets shot this turn.
Let the outermost bullet of the main clip quit(make it disappear), and tell you whether the bullet was true or false.
Let the number of the opposite's dazing turn increase by 1.
Suppose your current HP is m(_m_∈N₊), hurting point is n(0≤_n_≤8,_n_∈N), if m_≤3+n/3, there is a probability of 100% that your HP will increase by 1; if m>3+n/3, there is a probability of pow(2,3+n/3−_m) that your HP will increase by 1.
Tells you whether it is true or false of the outermost bullet of each clip (the top message describes the main clip's).
If the opposite has n(_n_∈N) non-limited tools, there is a probability of
1/(n+1) of gaining a non-limited tool equally likely, and a probability of
1−1/(n+1) of fetching 1 non−limited tool from the opposite equally likely.
The two are opposite events.
This is an OP tool.
Share the opposite's tool warehouse with you, and you will not be able to use
the tools in your warehouse at that time. There is a 30% chance of sharing 1
round, a 50% chance of sharing 2 rounds, and a 20% chance of sharing 3 rounds.
All three are mutually exclusive.
Append a bulletproof wearing with a durability exponent of 3 to the outermost
layer. When you have at least 1 bulletproof wearing, when a bullet is shot at
you, suppose the extra damage value of the turn is n(_n_∈N), the
outermost bulletproof wearing will first reduce randint(1,⌈√(n+1)⌉) points of
durability exponent. Subsequently, suppose the durability exponent of the
outermost bulletproof wearing is m(_m_∈Z), if m<0, the bulletproof
wearing has a probability of 1−pow(2,m) of disappearing.
If 1 bulletproof wearing disappears, your break care potential increases by 1;
if there is no bulletproof weareing after the bulletproof wearing disappears,
each point of your break care potential has a probability of 15% of turning
into a point of break care round, and a probability of 85% of nothing
happening. If the point of break care rounds is greater than 0, you will not be
able to use any tools in the following rounds, and you will randomly shoot at
either yourself or the opposite, and the point of break care rounds will
decrease by 1 for every 1 round that passes.
Not Implemented Yet
Let m=randint(1,6)+randint(1,6)+randint(1,6). If m=3, you will break care for 2 rounds; if m=4, your HP will decrease by 2 and tell you so; if m=5, the true-false state of the bullets in the main clip changes randomly from the outside to the inside from the 3rd bullet; if m=6, your HP will decrease by 1 and tell you so; if m=7, one of your non-limited tools disappears; if m=9, your stamina will increase by 1 until reaching the maximum; if m=10, your HP will increase by 1 and tell you so; if m=11, your stamina will increase by 2 until reaching the maximum; if m=12, your additional damage for the current turn will increase by 2, and there is a probability of 50% that you will be told so; if m=13, the opposite's HP will decrease by 1 and tell you so; if m=14, the opposite has a probability of 1/3 of being dazed for 1 more turn, and a probability of 2/3 of being dazed for 2 more turns, which are opposite events; if m=15, the opposite's HP will decrease by 2 and tell you so; if m=18, the opposite's HP will become 1/8th of what it was originally (floored), and tell you so.
Suppose you currently have n(_n_∈N) temporary slots. If n=0, this tool will not be used; if n>0, for each temporary slot, there is a 100% probability of postponing 1 round.
This is an OP tool.
For HP, hurting point, stamina, tool warehouse, stacked goodgun(foo), stacked
goodgun(bar), additional damage of current turn, bulletproof wearings, stacked
bullet catcher, stacked repeater, stacked combo shooter, stacked badgun,
stacked bandage, there is a probability of 50% that yours become the
opposite's, and tells “You've turned into the Evil”; there is a probability of
50% that the opposite's become yours, and tells “The Evil has turned into you”.
The two are opposite events.
And your and the opposite's dazing turns will become 0.
Let your stacked bullet catcher increase by 1. Suppose you currently have n(_n_∈N₊) stacked bullet catchers, the opposite's additional damage is m(_m_∈N), if the opposite shoots 1 true bullet, there is a probability of (1−0.8ⁿ)/(1+m) that you will catch it(avoids the damage from the bullet and tells you “You caught a bullet”) and put it into the tail of the main clip, and let your stacked bullet catcher be 0; if the opposite shoots 1 false bullet, there is a probability of 0.8/(1+m) that you will catch it(tells you “You caught a bullet”) and put it into the tail of the main clip, and let your stacked bullet catcher decrease by 1.
Suppose there are n(_n_∈N₊) bullets in the main clip now, then for each false bullet in the main clip there is a probability of 1/n that it will become a true bullet. If at least one false bullet becomes a true bullet, the message “The clip has changed” will be displayed.
Temporarily take all bullets in the main clip out and put them back to the main
clip one by one. You can specify where to put each bullet, but whether it is a
true bullet or a false bullet that is put back in will only be shown when it is
put in. For example, in the following case: 0T1F2T3T4F5, inputting 0 will
place one bullet in the outermost part of the main clip, inputting 5 will
place one bullet in the innermost part of the main clip, and inputting 3 will
place one bullet in the location of the two continuous true bullets in the
example. After all bullets have been put, the message “You've arranged the
bullets” will be displayed.
Let your stacked repeater count increase by 1.
See Tool 18: Lián Fā Shè Shǒu
Let your stacked combo shooter count increase by 1.
Suppose currently you have m(_m_∈N) stacked repeaters, n(_n_∈N)
stacked combo shooters, amount of the bullets in main clip is r(_r_∈N₊),
if you shoot at the opposite, then at least min(r,1+m) bullets will be
shot, and there will be a probability of 1−2⁻ⁿ shooting 1 more bullet(if there
exists a bullet in the clip). In other words, when n>0, there is a
probability of min(1,pow(1−2⁻ⁿ,r_−1−_m)) of clearing the clip. Suppose
s(_s_∈N₊) bullets are shot from the main clip, if s>n, then your
stacked combo shooter will become 0; if s_≤_n, then your stacked combo
shooter will decrease by s. For each additional shot bullet(by stacked
repeater), it makes stacked repeater count decrease by 1.
This is an OP tool.
There is a probability of 50% that you will be given an OP tool that does not
exceed the sending limit (not counted in the total number of shots given out)
and a probabulity of 50% that your HP will be halved (floored after halving).
The two are opposite events.
Not Implemented Yet
Increase the opposite's stacked badgun by 1.
Suppose the current explosion exponent is h(_h_∈N), your stacked
goodgun(foo) count is m(_m_∈N), your stacked goodgun(bar) count is
n(_n_∈N), and your stacked badgun number is r(_r_∈N). If shooting
at oneself, when r>0, there is a 100% probability of exploding for each
bullet shot; when r=0 and m>0, there is a 0% probability of exploding for
each bullet shot; otherwise, there is a probability of
(1−pow(1023/1024,h+200))² of exploding for each bullet shot. If shooting at
the opposite, when r>0, there is a 100% probability of exploding for each
bullet shot; when r=0 and n>0, there is a 0% probability of exploding for
each bullet shot; otherwise, there is a probability of
(1−pow(1023/1024,h+200))² of exploding for each bullet shot. The explosion
exponent increases by 1 when each bullet shot (whether exploded or not).
Take 1 bullet from the location you specified out from the main clip and change it to a tool Shí Dàn or Kōng Dàn and tell you so.
Put 1 false bullet into a location specified by you in the main clip and tell you so.
Put 1 true bullet into a location specified by you in the main clip and tell you so.
Put 1 mysterious bullet into a location specified by you in the main clip and
tell you so.
A “mysterious bullet” is a bullet whose true-false state is unknown and which
has a probability of 50% of affecting the true-false state of the bullet next
to the bullet put directioned inside (if exists).
Decrease your hurting point by 1 after 2 rounds. If the number of current pending bandages is greater than or equal to your hurting point, this tool will not be used.
If you have less than 2 HP, make you regain 5 HP; if you have less than 5 HP, make you regain 4 HP; if you have less than 9 HP, make you regain 3 HP; if you have less than 14 HP, make you regain 2 HP; if you have more than or equal to 14 HP, make you regain 1 HP. Additionally, if you have 0 hurting points, make you get 2 HP back, and if you have less than 4 hurting points, make you get 1 HP back. HP regained based on HP are told to you, while HP regained based on hurting points are not told to you.
Instantly give a batch of new clips(current clips will not be retained).
This is an OP tool.
Add 1 xor 2 extra clips. Just added by copying existing clips to new extra
clips. It will not prompt.
This is an OP tool.
There is a probability of 50% that both sides' tool warehouses and bulletproof
wearings will be cleared, and the additional damage will become zero.
This is an OP tool.
Suppose currently the main clip contains n(_n_∈N₊) bullets, make the
opposite's dazing turns increase by n.
This is an OP tool.
Initiate a stage battle, you and your opponent need to wager a certain amount
of HP(integer, min 1, max current HP), which your opponent cannot refuse.
During a stage battle, a batch of infinite bullet clips will be given out, and
your and your opponent's wager will be the initial HP for the stage battle. No
tools will be given out. When one side's HP reaches 0 or less, the other side
wins the stage battle and then receives the sum of their bets' HPs, and the
stage battle ends.
Make the explosion exponent 2/3 of what it was(floored) and tell you “You've mended the barrel”. If the explosion exponent is less than or equal to 0, this tool will not be used.
For each clip, move all true bullets in it to the outermost place, all false bullets in it to the innermost place and prompt “The clip has done 空实分离”.
Move the bullets in each extra clip (0→1→2 order) to the end of the main clip in their original order, and prompt “You've merged the clips”. If there are no extra clips or no bullets in all extra clips, this tool will not be used.
Only 1 period.
Your and the Evil's initial HP respectively are 1 and 10.
All tools except ID10 will be sent.
Each side has 8 permanent slots.
Only 1 period.
Your and the Evil's initial HP respectively are 2 and (2⁶⁴−1).
All tools except ID10, ID11 and ID13 will be sent.
Each side has 9 permanent slots.
Only 1 period.
Your and the Evil's initial HP respectively are 1 and 10.
Only tool ID2 and ID3 will be sent.
Each side has 100 permanent slots.
No temporary slot will be sent.
Only 1 period.
Your and the Evil's initial HP respectively are 50 and randint(50,90).
Only tool ID11 will be sent.
Each side has 100 permanent slots.
No temporary slot will be sent.
There are infinite periods.
Your initial HP is 2. Suppose the current period is Period n(_n_∈N₊), the
Evil's initial HP is (n+9).
All tools except ID10 will be sent.
Each side has 9 permanent slots.
Only 1 period.
Your and the Evil's initial HP respectively are 40 and 200.
Only tool ID0, ID1, ID2, ID9, ID15, ID17, ID18, ID21, ID27, ID28, ID29, ID34
and ID35 will be sent.
Each side has 12 permanent slots.
Only 1 period.
Your and the Evil's initial HP respectively are 10 and 50.
Only tool ID5, ID9, ID21 will be sent.
Each side has 6 permanent slots.
Only 1 period.
Your and the Evil's initial HP respectively are 18 and 50.
No tools will be sent.
Each side has 0 permanent slots.
No temporary slot will be sent.
Predefined game modes are in emlpd.gameinst, defined by
GAMEMODE_SET. This is the default setting of GAMEMODE_SET:
from typing import Dict, Iterable, Optional, Tuple, Union
from emlpd.gameapi import Game
class NormalGame(Game): ...
normal_mode: NormalGame = ...
infinite_mode: NormalGame = ...
xiaodao_party: NormalGame = ...
dice_kingdom: NormalGame = ...
class InfiniteMode2: ...
combo_party: NormalGame = ...
exploded_test: NormalGame = ...
onlybyhand: NormalGame = ...
GAMEMODE_SET: Dict[int, Union[
Tuple[Iterable[Game], int, float],
Tuple[Iterable[Game], int, float, str, Optional[str]]
]] = {
1: ((normal_mode,), 2, 2.5, "普通模式", "新手入门首选"),
2: ((infinite_mode,), 2, 2.5, "无限模式(一)", "陪你到天荒地老"),
3: ((xiaodao_party,), 3, 3., "小刀狂欢", "哪发是实弹?"),
4: ((dice_kingdom,), 4, 2.25, "骰子王国", "最考验运气的一集"),
5: (InfiniteMode2(), 2, 2.5, "无限模式(二)",
"霓为衣兮风为马,云之君兮纷纷而来下"),
6: ((combo_party,), 3, 2.5, "连射派对", "火力全开"),
7: ((exploded_test,), 2, 1.75, "炸膛测试", "枪在哪边好使?"),
8: ((onlybyhand,), 1, 2.5, "赤手空“枪”", "没有道具了")
}You need to create a Python script, create a Game object(which is defined in
emlpd.gameapi) in it, and add it into GAMEMODE_SET, for example:
from emlpd.gameapi import Game
from emlpd.gameinst import GAMEMODE_SET, gen_tools_from_generic_tools
my_gamemode: Game = Game( # For parameters' detail, see Game.__doc__
2,
10,
8,
0,
10,
100,
90,
gen_tools_from_generic_tools(
(0, 1, 21) # Include predefined tools' IDs, can be empty; see
# emlpd.gameinst.GENERIC_TOOLS
),
{
0: 1,
1: 1,
21: 2
},
{
0: 0,
1: 0,
21: 0
},
{
0: 2,
1: 2,
21: 4
},
7,
False
)
GAMEMODE_SET[
9 # Game mode ID
] = (
(my_gamemode,), # An iterable includes Game
1, # Specify the maximal tools sent per round for both side
2.75, # Specify the EXP multiplier
"Game Mode Name",
"Game Mode Description"
)
import emlpd.__main__ # type: ignore # import cannot be omitted!And run the script above, you will see:
Game Mode 9: Game Mode Name
Introduction: Game Mode Description
Input 9 for entering custom game mode.
Python 3.6 or above is required.
Type python -m emlpd.classic lang=en_en in the terminal.
You need to follow the hints given to you in the game interface to defeat the
Evil. To defeat the Evil, you need to make the Evil's HP 0 or less and your HP
above 0.
At the beginning of each round, the game will tell you the counts of true and
false bullets are in the clip. Each turn, you can choose to shoot at yourself
or the opposite.
If you shoot at yourself and the bullet is a false bullet, you will shoot again
in the next turn, otherwise the opposite will shoot.
If 1 true bullet is shot, it causes 1 point of base damage.
If a side have n(_n_∈N₊) dazing turns, then if it would have been this
side to shoot in the next turn, then the opposite still shoots in the next turn
and the number of this side's dazing turns becomes _n_−1.
Shooting 1 time is called 1 turn.
Giving 1 new clips is called 1 round.
Game running 1 time is called 1 game.
If n(_n_∈N) Xiǎo Dāos is used this turn, attach n points of additional damage for each true bullets shot this turn.
Let the outermost bullet of the clip quit(make it disappear), and tell you whether the bullet was true or false.
Let the number of the opposite's dazing turn increase by 1.
Suppose your current HP is m(_m_∈N₊), if m_≤3, there is a probability of 100% that your HP will increase by 1; if m>3, there is a probability of pow(2,3−_m) that your HP will increase by 1.
Tells you whether it is true or false of the outermost bullet of the clip.