Given a binary tree, find the lowest common ancestor (LCA) of two given nodes in the tree.
According to the definition of LCA on Wikipedia:
“The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (where we allow a node to be a descendant of itself).”
_______3______
/ \
___5__ ___1__
/ \ / \
6 _2 0 8
/ \
7 4
For example, the lowest common ancestor (LCA) of nodes 5
and 1
is 3
.
Another example is LCA of nodes 5
and 4
is 5
, since a node can be a descendant of itself according to the LCA definition.
public TreeNode lowestCommonAncestor(TreeNode root, TreeNode p, TreeNode q) {
if (root == null || root == p || root == q) {
return root;
}
TreeNode right = lowestCommonAncestor(root.right, p, q);
TreeNode left = lowestCommonAncestor(root.left, p, q);
if (left == null) {
return right;
} else if (right == null) {
return left;
} else {
// both of them is not null
return root;
}
}
- (TreeNode *)lowestCommonAncestor:(TreeNode *)root withP:(TreeNode *)p withQ:(TreeNode *)q {
if (root == nil || root == p || root == q) {
return root;
}
TreeNode *left = [self lowestCommonAncestor:root.left withP:p withQ:q];
TreeNode *right = [self lowestCommonAncestor:root.right withP:p withQ:q];
if (left == nil) {
return right;
} else if (right == nil) {
return left;
} else {
return root;
}
}