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grid2div.vic_dly.f
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program gcon
c
real data(5684)
real pinc, tinc, t42lg, t42lt, seas(1916:2018,12,31,344)
real out(12), grid(116,49)
real xdat(116,49,9)
real dgrid(344,100)
integer lgrid(344,100), min, max
integer state(344), div(344), vn(344)
integer year(1916:2018,12)
integer monthday(12)
c
c
open(1,file='116x49.to.div.info')
open(3,file='/projects/lsm/vic_soilliq3.dly.1916.2018_06')
c
monthday(1) = 31
monthday(2) = 28
monthday(3) = 31
monthday(4) = 30
monthday(5) = 31
monthday(6) = 30
monthday(7) = 31
monthday(8) = 31
monthday(9) = 30
monthday(10) = 31
monthday(11) = 30
monthday(12) = 31
c
do ndv = 1, 344
read(1, '(3i5)') state(ndv), div(ndv), n
read(1, '(12i6)') (lgrid(ndv,i),i=1,n)
read(1, '(12f6.1)') (dgrid(ndv,i),i=1,n)
vn(ndv) = n
enddo
c
do iy = 1916, 2018
do im = 1, 12
do id = 1, 31
do idv = 1, 344
seas(iy,im,id,idv) = -99.
enddo
enddo
enddo
enddo
c
open(2,file='/projects/lsm/vic/lsm_vic.dly.191601_201806',
+form='unformatted',
+access='direct',recl=116*49*9*4)
c
nrec = 0
do iy = 1916, 2018
c
mth = 12
if(iy .eq. 2018) mth = 6
do im = 1, mth
c
if(mod(iy,4) .eq. 0) then
if(mod(iy,100) .eq. 0.0) then
monthday(2) = 28
if(mod(iy,400) .eq. 0) monthday(2) = 29
else
monthday(2) = 29
endif
else
monthday(2) = 28
endif
c
do k = 1, 12
year(iy,k) = monthday(k)
enddo
c
mth = 12
if(iy .eq. 2018) mth = 6
c
do id = 1, monthday(im)
nrec = nrec + 1
read(2,rec=nrec) (((xdat(j,k,i),j=1,116),k=1,49),i=1,9)
print*, iy, im, id, nrec
do j = 1, 116
do k = 1, 49
grid(j,k) = xdat(j,k,8)
enddo
enddo
c
n = 1
do k = 1, 49
do j = 1, 116
data(n) = grid(j,k)
n = n + 1
enddo
enddo
c
do ndv = 1, 344
xx = 0.0
xxc = 0.0
n = vn(ndv)
do i = 1, n
if(dgrid(ndv,i) .lt. 5.) dgrid(ndv,i) = 5.
if(dgrid(ndv,i) .gt. 200.) goto 17
if(data(lgrid(ndv,i)) .gt. -90.) then
xx = xx + (data(lgrid(ndv,i)) * (1./(dgrid(ndv,i)**2.)))
xxc = xxc + (1. / (dgrid(ndv,i)**2.))
endif
17 continue
enddo
if(xxc .gt. 0.0) then
xx = xx / xxc
else
xx = -99.
endif
seas(iy,im,id,ndv) = xx
c
enddo
c.. day
enddo
c.. month
enddo
c.. year
enddo
c
do ndv = 1, 344
do iy = 1916, 2018
mth = 12
if(iy .eq. 2018) mth = 6
do im = 1, mth
n = year(iy,im)
write(3,18) state(ndv),div(ndv),iy,im,n,(seas(iy,im,i,ndv),i=1,n)
18 format(2i2,i5,2i3,31f7.1)
enddo
enddo
enddo
c
end