-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy path80.remove-duplicates-from-sorted-array-ii.ts
112 lines (109 loc) · 2.97 KB
/
80.remove-duplicates-from-sorted-array-ii.ts
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
/*
* @lc app=leetcode id=80 lang=typescript
*
* [80] Remove Duplicates from Sorted Array II
*
* https://leetcode.com/problems/remove-duplicates-from-sorted-array-ii/description/
*
* algorithms
* Medium (53.97%)
* Likes: 6210
* Dislikes: 1175
* Total Accepted: 730.8K
* Total Submissions: 1.3M
* Testcase Example: '[1,1,1,2,2,3]'
*
* Given an integer array nums sorted in non-decreasing order, remove some
* duplicates in-place such that each unique element appears at most twice. The
* relative order of the elements should be kept the same.
*
* Since it is impossible to change the length of the array in some languages,
* you must instead have the result be placed in the first part of the array
* nums. More formally, if there are k elements after removing the duplicates,
* then the first k elements of nums should hold the final result. It does not
* matter what you leave beyond the first k elements.
*
* Return k after placing the final result in the first k slots of nums.
*
* Do not allocate extra space for another array. You must do this by modifying
* the input array in-place with O(1) extra memory.
*
* Custom Judge:
*
* The judge will test your solution with the following code:
*
*
* int[] nums = [...]; // Input array
* int[] expectedNums = [...]; // The expected answer with correct length
*
* int k = removeDuplicates(nums); // Calls your implementation
*
* assert k == expectedNums.length;
* for (int i = 0; i < k; i++) {
* assert nums[i] == expectedNums[i];
* }
*
*
* If all assertions pass, then your solution will be accepted.
*
*
* Example 1:
*
*
* Input: nums = [1,1,1,2,2,3]
* Output: 5, nums = [1,1,2,2,3,_]
* Explanation: Your function should return k = 5, with the first five elements
* of nums being 1, 1, 2, 2 and 3 respectively.
* It does not matter what you leave beyond the returned k (hence they are
* underscores).
*
*
* Example 2:
*
*
* Input: nums = [0,0,1,1,1,1,2,3,3]
* Output: 7, nums = [0,0,1,1,2,3,3,_,_]
* Explanation: Your function should return k = 7, with the first seven
* elements of nums being 0, 0, 1, 1, 2, 3 and 3 respectively.
* It does not matter what you leave beyond the returned k (hence they are
* underscores).
*
*
*
* Constraints:
*
*
* 1 <= nums.length <= 3 * 10^4
* -10^4 <= nums[i] <= 10^4
* nums is sorted in non-decreasing order.
*
*
*/
// @lc code=start
function removeDuplicates(nums: number[]): number {
let counter = 0,
pre = NaN;
for (let i = 0; i < nums.length; i++) {
if (pre === nums[i]) counter++;
else {
counter = 1;
pre = nums[i];
}
if (counter > 2) nums[i] = NaN;
}
counter = 0;
for (let i = 0; i < nums.length; i++) {
if (Number.isNaN(nums[i])) {
for (let j = i + 1; j < nums.length; j++) {
if (Number.isNaN(nums[j])) continue;
nums[i] = nums[j];
nums[j] = NaN;
break;
}
if (Number.isNaN(nums[i])) break;
}
counter++;
}
return counter;
}
// @lc code=end