-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy path167.two-sum-ii-input-array-is-sorted.ts
106 lines (105 loc) · 2.71 KB
/
167.two-sum-ii-input-array-is-sorted.ts
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
/*
* @lc app=leetcode id=167 lang=typescript
*
* [167] Two Sum II - Input Array Is Sorted
*
* https://leetcode.com/problems/two-sum-ii-input-array-is-sorted/description/
*
* algorithms
* Medium (60.15%)
* Likes: 10385
* Dislikes: 1270
* Total Accepted: 1.6M
* Total Submissions: 2.6M
* Testcase Example: '[2,7,11,15]\n9'
*
* Given a 1-indexed array of integers numbers that is already sorted in
* non-decreasing order, find two numbers such that they add up to a specific
* target number. Let these two numbers be numbers[index1] and numbers[index2]
* where 1 <= index1 < index2 < numbers.length.
*
* Return the indices of the two numbers, index1 and index2, added by one as an
* integer array [index1, index2] of length 2.
*
* The tests are generated such that there is exactly one solution. You may not
* use the same element twice.
*
* Your solution must use only constant extra space.
*
*
* Example 1:
*
*
* Input: numbers = [2,7,11,15], target = 9
* Output: [1,2]
* Explanation: The sum of 2 and 7 is 9. Therefore, index1 = 1, index2 = 2. We
* return [1, 2].
*
*
* Example 2:
*
*
* Input: numbers = [2,3,4], target = 6
* Output: [1,3]
* Explanation: The sum of 2 and 4 is 6. Therefore index1 = 1, index2 = 3. We
* return [1, 3].
*
*
* Example 3:
*
*
* Input: numbers = [-1,0], target = -1
* Output: [1,2]
* Explanation: The sum of -1 and 0 is -1. Therefore index1 = 1, index2 = 2. We
* return [1, 2].
*
*
*
* Constraints:
*
*
* 2 <= numbers.length <= 3 * 10^4
* -1000 <= numbers[i] <= 1000
* numbers is sorted in non-decreasing order.
* -1000 <= target <= 1000
* The tests are generated such that there is exactly one solution.
*
*
*/
// @lc code=start
function twoSum(numbers: number[], target: number): number[] {
/**
* Solution 1
*/
// let index1 = 0;
// function find(target: number, left: number, right: number) {
// while (left <= right) {
// const mid = Math.floor((left + right) / 2);
// if (target === numbers[mid]) return mid;
// else if (target < numbers[mid]) right = mid - 1;
// else if (target > numbers[mid]) left = mid + 1;
// }
// return -1;
// }
// while (index1 < numbers.length) {
// const number1 = numbers[index1];
// const rest = target - number1;
// const resIdx = find(rest, index1 + 1, numbers.length - 1);
// if (resIdx !== -1) return [index1 + 1, resIdx + 1];
// index1++;
// }
// return [0, 0];
/**
* Solution 2
*/
let left = 0,
right = numbers.length - 1;
while (left < right) {
const res = numbers[left] + numbers[right];
if (res === target) return [left + 1, right + 1];
if (res > target) right--;
else left++;
}
return [0, 0];
}
// @lc code=end