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112.path-sum.js
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/*
* @lc app=leetcode id=112 lang=javascript
*
* [112] Path Sum
*
* https://leetcode.com/problems/path-sum/description/
*
* algorithms
* Easy (41.06%)
* Likes: 2276
* Dislikes: 533
* Total Accepted: 513K
* Total Submissions: 1.2M
* Testcase Example: '[5,4,8,11,null,13,4,7,2,null,null,null,1]\n22'
*
* Given a binary tree and a sum, determine if the tree has a root-to-leaf path
* such that adding up all the values along the path equals the given sum.
*
* Note: A leaf is a node with no children.
*
* Example:
*
* Given the below binary tree and sum = 22,
*
*
* 5
* / \
* 4 8
* / / \
* 11 13 4
* / \ \
* 7 2 1
*
*
* return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.
*
*/
// @lc code=start
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @param {number} sum
* @return {boolean}
*/
var hasPathSum = function (root, sum) {
if (!root) return false;
return hasPathSumRecursive(root, sum, 0);
};
function hasPathSumRecursive(root, sum, val) {
let newVal = val + root.val,
left = false,
right = false;
if (!root.left && !root.right) {
return newVal === sum;
}
if (root.left) {
left = hasPathSumRecursive(root.left, sum, newVal);
}
if (root.right) {
right = hasPathSumRecursive(root.right, sum, newVal);
}
return left || right;
}
// @lc code=end
// [5,4,8,11,null,13,4,7,2,null,null,null,1]\n26
// []\n0
// [2]\n2
// [1,2]\n1