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给你两个单词 word1 和 word2, 请返回将 word1 转换成 word2 所使用的最少操作数 。
你可以对一个单词进行如下三种操作:
插入一个字符 删除一个字符 替换一个字符 示例 1:
输入:word1 = "horse", word2 = "ros" 输出:3 解释: horse -> rorse (将 'h' 替换为 'r') rorse -> rose (删除 'r') rose -> ros (删除 'e') 示例 2:
输入:word1 = "intention", word2 = "execution" 输出:5 解释: intention -> inention (删除 't') inention -> enention (将 'i' 替换为 'e') enention -> exention (将 'n' 替换为 'x') exention -> exection (将 'n' 替换为 'c') exection -> execution (插入 'u')
var minDistance = function(word1, word2) { const dp = Array.from({ length: word2.length + 1 }, (item, index) => index); // 保存的是左上角的值 let before; for (let i = 1; i <= word1.length; i++) { before = dp[ 0 ]; dp[ 0 ] = i; for (let j = 1; j < dp.length; j++) { // 先将左上角值缓存,后续在进行更新 const temp = dp[ j ]; const flag = word1[i - 1] === word2[j - 1] ? 1 : 0; dp[j] = 1 + Math.min(dp[j - 1], dp[j], before - flag); before = temp; } } return dp[ dp.length - 1 ] };
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