class Solution(object):
def getKth(self, A, B, k):
k = int(k)
lenA = len(A); lenB = len(B)
if lenA > lenB: return self.getKth(B, A, k)
if lenA == 0: return B[k - 1]
if k == 1: return min(A[0], B[0])
pa = min(int(k/2), lenA); pb = k - pa
if A[pa - 1] <= B[pb - 1]:
return self.getKth(A[pa:], B, pb)
else:
return self.getKth(A, B[pb:], pa)
def findMedianSortedArrays(self, A, B):
lenA = len(A); lenB = len(B)
if (lenA + lenB) % 2 == 1:
return self.getKth(A, B, int((lenA + lenB)/2) + 1)
else:
return (self.getKth(A, B, (lenA + lenB)/2) + self.getKth(A, B, (lenA + lenB)/2 + 1)) * 0.5
数组 查找 二分