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If a well has a rate control of 1000 and an efficiency factor of 0.5, is the simulator is sending 500 or 1000 to the output? If 500 then the above calculation is correct, so I guess that means it sends 1000?
The rate will still be 1000, while the accumulated amount WWPT will need to consider the efficiency factor when multiplied with operation time, just thinking it is as work 50% of the time.
This can be fixed in the output code by quarrying the efficiency factor for wells and groups from the parser and apply it here and in similar places.
An alternative is to add the efficiency factor itself to the well data passed to the output code. I would think that is a bit simpler? Unless the output code would need to get the efficiency factors for groups etc. for other reasons anyway; then we should do as you suggest.
Currently the output code does not take into account the well efficiency factor.
The total water production is in the current code:
This can be fixed in the output code by quarrying the efficiency factor for wells and groups from the parser and apply it here and in similar places.
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