https://leetcode.com/problems/validate-stack-sequences/
Given two sequences pushed
and popped
with distinct values, return true
if and only if this could have been the result of a sequence of push and pop operations on an initially empty stack.
Example 1:
Input: pushed = [1,2,3,4,5], popped = [4,5,3,2,1]
Output: true
Explanation: We might do the following sequence:
push(1), push(2), push(3), push(4), pop() -> 4,
push(5), pop() -> 5, pop() -> 3, pop() -> 2, pop() -> 1
Example 2:
Input: pushed = [1,2,3,4,5], popped = [4,3,5,1,2]
Output: false
Explanation: 1 cannot be popped before 2.
Constraints:
0 <= pushed.length == popped.length <= 1000
0 <= pushed[i], popped[i] < 1000
pushed
is a permutation ofpopped
.pushed
andpopped
have distinct values.
class Solution {
public:
bool validateStackSequences(vector<int>& pushed, vector<int>& popped) {
stack<int> s;
int i = 0;
for (int x : pushed) {
s.push(x);
while (!s.empty() && s.top() == popped[i]) {
s.pop();
i++;
}
}
return s.empty();
}
};
class Solution:
def validateStackSequences(self, pushed: List[int], popped: List[int]) -> bool:
stack = []
for i in pushed:
stack.append(i)
while stack and popped and stack[-1] == popped[0]:
# stack top
stack.pop()
popped.pop(0)
return not stack