Function evaluation returns value of future definition

[caprilo]

The return value of a function is determined by the function as defined in the last appearance in the code, instead of the value of the function as it is defined at the moment of the evaluation. Take, for instance

function f()
   g() = 1
   return g()
   g() = 2
end

When calling f() it returns 2, even if the definition of g as the constant function 2 was never reached. I would expect this code to return 1.

versioninfo()

Julia Version 1.0.1
Commit 0d71392 (2018-09-29 19:05 UTC)
Platform Info:
OS: Linux (x86_64-pc-linux-gnu)
CPU: Intel(R) Core(TM) i7-8550U CPU @ 1.80GHz
WORD_SIZE: 64
LIBM: libopenlibm
LLVM: libLLVM-6.0.0 (ORCJIT, skylake)

[fredrikekre]

Duplicate of #15602