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How to define Package Name arg #14
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Try 'ros2srrc_execution' as the package name. This is the place where the program 'ur3' lies |
Thanks for your answer. This seems to work. What else do I need to launch to start the action server? Something like: |
There were some changes to the launch files and I dont know exactly what the launch command should look like because Im using an older version. |
Thanks for your help. I am now able to launch a robot simulation using: |
What does work though is: |
Hi, |
Hi,
after completing the installation, I tried to run the example from this video.
ros2 run ros2srrc_execution sequence.py --ros-args -p PROGRAM_FILENAME:="ur3" -p ROBOT_MODEL:="ur3" -p EE_MODEL:="robotiq_2f85" -p GzBr_ENV:="gazebo"
I am receiving this error:
Please execute the program and input all ROS2 parameters in the Ubuntu Terminal as stated below:
COMMAND -> ros2 run ros2srrc_execution sequence.py --ros-args -p PACKAGE_NAME:= "---" -p PROGRAM_FILENAME:="---" -p ROBOT_MODEL:="---" -p EE_MODEL:="---" -p GzBr_ENV:="---"
I'm guessing I have to add the "PACKAGE_NAME" arg. But what options do I have?
There are no options for "PACKAGE_NAME" in the readme
Thanks in advance.
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