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shopping_trip.cpp
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/**
* BGL-Flow problem: the nodes are the intersections and to every street is given a capacity of one (in both the directions, as streets are undirected).
* The capacity from the source to the intersection 0 is equal to the number of shops and from every shop there's an outcoming edge with capacity 1 directed to the sink.
* If the flow equals the number of shops, the answer is yes: otherwise, it's no.
**/
#include <iostream>
#include <vector>
#include <algorithm>
#include <boost/graph/adjacency_list.hpp>
#include <boost/graph/push_relabel_max_flow.hpp>
typedef boost::adjacency_list_traits<boost::vecS, boost::vecS, boost::directedS> traits;
typedef boost::adjacency_list<boost::vecS, boost::vecS, boost::directedS, boost::no_property, boost::property<boost::edge_capacity_t, long, boost::property<boost::edge_residual_capacity_t, long, boost::property<boost::edge_reverse_t, traits::edge_descriptor>>>> graph;
typedef traits::vertex_descriptor vertex_desc;
typedef traits::edge_descriptor edge_desc;
class edge_adder {
graph &G;
public:
explicit edge_adder(graph &G) : G(G) {}
void add_edge(int from, int to, long capacity) {
auto c_map = boost::get(boost::edge_capacity, G);
auto r_map = boost::get(boost::edge_reverse, G);
const auto e = boost::add_edge(from, to, G).first;
const auto rev_e = boost::add_edge(to, from, G).first;
c_map[e] = capacity;
c_map[rev_e] = 0;
r_map[e] = rev_e;
r_map[rev_e] = e;
}
};
using namespace std;
int main(int argc, char const *argv[]) {
ios_base::sync_with_stdio(false);
cin.tie(0);
int t;
cin >> t;
while(t--) {
int n, m, s;
cin >> n >> m >> s;
graph g(n);
const vertex_desc source = boost::add_vertex(g);
const vertex_desc target = boost::add_vertex(g);
edge_adder adder(g);
adder.add_edge(source, 0, s);
for(int i = 0; i < s; i++) {
int store;
cin >> store;
adder.add_edge(store, target, 1);
}
for(int i = 0; i < m; i++) {
int from, to;
cin >> from >> to;
adder.add_edge(from, to, 1);
adder.add_edge(to, from, 1);
}
long flow = boost::push_relabel_max_flow(g, source, target);
flow == s ? cout << "yes\n" : cout << "no\n";
}
}