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mongoRetrivChange3.py
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from pymongo import MongoClient as mc
import re
import string
import getword
client=mc()
db=client.kbmain
def removePandS(content):
re.sub(r'\b\w{,2}\b',' ', content)
re.sub(r'\b\w{15,}\b',' ', content)
regex=re.compile('[%s]'% re.escape(string.punctuation))
content=re.sub(regex," ",content)
stop_words=set(["a","a's","belongs","able","about","above","according","accordingly","across","actually","after","afterwards","again","against","ain't","all","allow","allows","almost","alone","along","already","also","although","always","am","among","amongst","an","and","another","any","anybody","anyhow","anyone","anything","anyway","anyways","anywhere","apart","appear","appreciate","appropriate","are","aren't","around","as","aside","ask","asking","associated","at","available","away","awfully","be","became","because","become","becomes","becoming","been","before","beforehand","behind","being","believe","below","beside","besides","best","better","between","beyond","both","brief","but","by","c'mon","c's","came","can","can't","cannot","cant","cause","causes","certain","certainly","changes","clearly","co","com","come","comes","concerning","consequently","consider","considering","contain","containing","contains","corresponding","could","couldn't","course","currently","definitely","described","despite","did","didn't","different","do","does","doesn't","doing","don't","done","down","downwards","during","each","edu","eg","eight","either","else","elsewhere","enough","entirely","especially","et","etc","even","ever","every","everybody","everyone","everything","everywhere","ex","exactly","example","except","far","few","fifth","first","five","followed","following","follows","for","former","formerly","forth","four","from","further","furthermore","get","gets","getting","given","gives","go","goes","going","gone","got","gotten","greetings","had","hadn't","happens","hardly","has","hasn't","have","haven't","having","he","he's","hello","help","hence","her","here","here's","hereafter","hereby","herein","hereupon","hers","herself","hi","him","himself","his","hither","hopefully","how","howbeit","however","i'd","i'll","i'm","i've","ie","if","ignored","immediate","in","inasmuch","indeed","indicate","indicated","indicates","inner","insofar","instead","into","inward","is","isn't","it","it'd","it'll","it's","its","itself","just","keep","keeps","kept","know","known","knows","last","lately","later","latter","latterly","least","less","lest","let","let's","like","liked","likely","little","look","looking","looks","ltd","mainly","many","may","maybe","me","mean","meanwhile","merely","might","more","moreover","most","mostly","much","must","my","myself","name","namely","nd","near","nearly","necessary","need","needs","neither","never","nevertheless","new","next","nine","no","nobody","non","none","noone","nor","normally","not","nothing","novel","now","nowhere","obviously","of","off","often","oh","ok","okay","old","on","once","one","ones","only","onto","or","other","others","otherwise","ought","our","ours","ourselves","out","outside","over","overall","own","particular","particularly","per","perhaps","placed","please","plus","possible","presumably","probably","provides","que","quite","qv","rather","rd","re","really","reasonably","regarding","regardless","regards","relatively","respectively","right","said","same","saw","say","saying","says","second","secondly","see","seeing","seem","seemed","seeming","seems","seen","self","selves","sensible","sent","serious","seriously","seven","several","shall","she","should","shouldn't","since","six","so","some","somebody","somehow","someone","something","sometime","sometimes","somewhat","somewhere","soon","sorry","specified","specify","specifying","still","sub","such","sup","sure","t's","take","taken","tell","tends","th","than","thank","thanks","thanx","that","that's","thats","the","their","theirs","them","themselves","then","thence","there","there's","thereafter","thereby","therefore","therein","theres","thereupon","these","they","they'd","they'll","they're","they've","think","third","this","thorough","thoroughly","those","though","three","through","throughout","thru","thus","to","together","too","took","toward","towards","tried","tries","truly","try","trying","twice","two","un","under","unfortunately","unless","unlikely","until","unto","up","upon","us","use","used","useful","uses","using","usually","value","various","very","via","viz","vs","want","wants","was","wasn't","way","we","we'd","we'll","we're","we've","welcome","well","went","were","weren't","what","what's","whatever","when","whence","whenever","where","where's","whereafter","whereas","whereby","wherein","whereupon","wherever","whether","which","while","whither","who","who's","whoever","whole","whom","whose","why","will","willing","wish","with","within","without","won't","would","wouldn't","yes","yet","you","you'd","you'll","you're","you've","your","yours","yourself","yourselves"])
a=" ".join(word for word in content.split() if word not in stop_words)
return a.split()
# this method gets the query from the gla
def queryRetriv(query):
print query
"""
-------- Varaible description --------
# keys --- type-list --- desc-Keywords obtained after GLA
# get --- type-cursor
# sendDict --- type-Dictionary --- desc- dictionary which contains data in the form {keyword: {fields in which its present along with the count}}
# keyword --- type-list --- desc- list which contains keywords which are field names in any collection
# fieldKeyword --- type-list --- desc- list which is used to store keywords which are field names in any collection
--------------------------------------
"""
keys=query.lower().split() #split the query obtained
print keys
get=db.newIndex2.find({"keyword":{"$in":keys}}) # select fields corresponding to the keywords from 'index' table
sendDict={}
get=list(get)
print get
store=get
#print get
# this is to make the fetched details proper
for ge in store:
ge.pop('_id')
keyword=ge["keyword"]
lis=ge.keys()
lis.pop(lis.index("keyword"))
sendDict[keyword]=lis
# print sendDict
keyword=[]
fieldKeyword=[]
if sendDict:
data=getIntersection(sendDict) # this is to get collections to which the given keywords are common
if not data:
data=[most_common(sendDict.values())]
#print data
anotherDict={}
for key in keys:
for dat in data:
for st in store:
if st["keyword"]==key:
if not anotherDict.has_key(dat):
anotherDict[dat]={}
if st.has_key(dat):
if type(st[dat]) is dict:
#types contains type of all the values of a dictionary
types=map(type,st[dat].values())
if st[dat].keys()==1:
if type(st[dat][st[dat].keys()[0]]) is dict:
dt={st[dat].keys()[0]:st[dat][st[dat].keys()[0]]}
else:
dt={key:st[dat]}
elif dict in types:
kys=sorted(st[dat].keys())
for k in kys:
if type(st[dat][k]) is dict:
dt={k:st[dat][k]}
break
else:
dt={key:st[dat]}
else:
dt={key:st[dat]}
anotherDict[dat].update(dt)
if str(st[dat])=="field":
fieldKeyword.append(key)
if not anotherDict[dat].has_key("priority"):
anotherDict[dat]["priority"]=10
else:
anotherDict[dat]["priority"]+=10
elif str(st[dat])=="categories":
fieldKeyword.append(key)
if not anotherDict[dat].has_key("priority"):
anotherDict[dat]["priority"]=30
else:
anotherDict[dat]["priority"]+=30
else:
if not anotherDict[dat].has_key("priority"):
anotherDict[dat]["priority"]=1
else:
anotherDict[dat]["priority"]+=1
keyword.append(key)
print sendDict
print "\n\n"
print anotherDict
print "\n\n"
return retrieveResults(anotherDict,keyword,fieldKeyword,keys)
def getIntersection(sendDict):
k=[]
k=map(set,sendDict.values())
inter=set(k[0]).intersection(*k)
return list(inter)
def most_common(lst1):
lst=[]
for l in lst1:
lst+=l
return max(set(lst), key=lst.count)
def retrieveResults(anotherDict,keyword,fieldKeywords,keys):
prio={}
part={}
for key in anotherDict.keys():
a=[]
prio[key]=anotherDict[key]["priority"]
if (key!='priority' and anotherDict[key]!='field'):
k=anotherDict[key].keys()
for field in anotherDict[key].keys():
if anotherDict[key][field]=="field" or anotherDict[key][field]=="categories" :
k.pop(k.index(field))
elif field!="priority":
prio[key]-=sum(anotherDict[key][field].values())
k.pop(k.index("priority"))
part[key]=k
return retrivAnswer(anotherDict,part,prio,keys,fieldKeywords)
def retrivAnswer(anotherDict,part,prio,keys,fieldKeywords):
#print prio
reqCollections=sortDict(prio)# these are the required collections with priority
#print reqCollections
for collection in reqCollections:
keywords=part[collection]
interList=[]
for keyword in keywords:
print keyword
interList+=anotherDict[collection][keyword].keys()
break
tempKey={}
coll=reqCollections[0]
interList=list(set(interList))
returnresult={}
for key in keys:
for field in interList:
#print key
#print anotherDict[coll].keys()
if not returnresult.has_key(field):
returnresult[field]=[]
if key in anotherDict[coll].keys():
print key
if anotherDict[coll].has_key(key):
if type(anotherDict[coll][key]) is dict:
if anotherDict[coll][key].has_key(field):
returnresult[field].append(key)
else:
get=getword.getwordtonum([key])
try:
key=list(set(get) & set(anotherDict[coll].keys()))[0]
if type(anotherDict[coll][key]) is dict:
if anotherDict[coll][key].has_key(field):
returnresult[field].append(key)
except:
pass
return printResult(reqCollections[0],returnresult,sortDictLen(returnresult),part[reqCollections[0]],keys,fieldKeywords)
def printResult(collection,returnresult,sodict,keys,keywords,fieldKeywords):
kinter=list(set(fieldKeywords) & set(sodict))
if kinter:
for kint in kinter:
sodict.pop(sodict.index(kint))
sodict=[kint]+sodict
mainQuery={}
mainQuery[collection]={}
checkList=[]
temp=[]
for key in sodict:
lis=returnresult[key]
if not temp:
temp+=lis
mainQuery[collection][key]=" ".join(lis)
mainQuery[collection][key]={}
mainQuery[collection][key]['$regex']="(?=.* "+(" .*)(?=.* ".join(lis))+" .*)"
mainQuery[collection][key]['$options']='-i'
elif not list(set(temp) & set(lis)):
temp+=lis
mainQuery[collection][key]={}
mainQuery[collection][key]['$regex']="(?=.* "+(" .*)(?=.* ".join(lis))+" .*)"
mainQuery[collection][key]['$options']='-i'
if len(list(set(temp)))==len(keys):
break
print mainQuery
collection=mainQuery.keys()[0]
ans = list(db[collection].find(mainQuery[collection]))
print ans
return ans
def sortDict(dicti):
lis=sorted(dicti, key=lambda key: dicti[key],reverse=True)
return lis
def sortDictLen(dicti):
lis=sorted(dicti, key=lambda key: len(dicti[key]),reverse=True)
return lis